-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathtreeNode.ts
144 lines (103 loc) · 2.5 KB
/
treeNode.ts
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
/**
* 二叉树 广度遍历
*/
class TreeNode {
value: number
left?: TreeNode
right?: TreeNode
constructor(value: number, left?: TreeNode, right?: TreeNode){
this.value = value;
this.left = left;
this.right = right;
}
}
const n4 = new TreeNode(4)
const n5 = new TreeNode(5)
const n6 = new TreeNode(6)
const n7 = new TreeNode(7)
const root = new TreeNode(1, new TreeNode(2, n4, n5), new TreeNode(3, n6, n7))
/**
* 二叉树广度遍历
* @param root 二叉树根节点
*/
function bfs(root: TreeNode) {
const queue = new Array<TreeNode>()
queue.push(root)
while(queue.length) {
let size = queue.length
console.log('当前层 size =', size);
for (let i = 0; i < size; i++) {
const node = queue.shift()!
console.log('node =', node.value);
if (node.left) queue.push(node.left)
if (node.right) queue.push(node.right)
}
}
}
/**
* 前序遍历
*/
console.log(root);
function preTravel(root?: TreeNode) {
if (root == null) return
console.log('前序遍历 =', root.value);
preTravel(root.left)
preTravel(root.right)
}
// preTravel(root)
/**
* 中序遍历
*/
function midTravel(root?: TreeNode) {
if (root == null) return
midTravel(root.left)
console.log('中序遍历 =', root.value);
midTravel(root.right)
}
// midTravel(root)
/**
* 后续遍历
*/
function backTravel(root?: TreeNode) {
if (root == null) return
backTravel(root.left)
backTravel(root.right)
console.log('后续遍历 =', root.value);
}
backTravel(root)
// bfs(root)
/**
* 从前序与中序遍历序列构造二叉树
* 前序:[1,2,5,4,6,7,3,8,9]
* 中序:[5,2,6,4,7,1,8,3,9]
*/
/**
* root = [1]
* leftTree = [5,2,6,4,7] 中序
* rightTree = [8,3,9] 中序
*/
/**
* 二叉树前序遍历
*/
// function preorderTraversal(root: TreeNode | null): number[] {
// // 先用递归
// const res = new Array()
// dfs(root, res)
// return res
// };
// function dfs(root: TreeNode | null, res: number[]) {
// if (root === null) return
// res.push(root.value)
// console.log('res =',res);
// if (root.left) {
// dfs(root.left, res)
// }
// if (root.right) {
// dfs(root.right, res)
// }
// }
// const n3 = new TreeNode(3)
// const n2 = new TreeNode(2, n3, null)
// const root = new TreeNode(1, null, n2)
// console.log(root);
// console.log(preorderTraversal(root));