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Copy path108. Convert Sorted Array to Binary Search Tree.cpp
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108. Convert Sorted Array to Binary Search Tree.cpp
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// 108. Convert Sorted Array to Binary Search Tree
// Solved
// Easy
// Topics
// Companies
// Given an integer array nums where the elements are sorted in ascending order, convert it to a
// height-balanced
// binary search tree.
// Example 1:
// Input: nums = [-10,-3,0,5,9]
// Output: [0,-3,9,-10,null,5]
// Explanation: [0,-10,5,null,-3,null,9] is also accepted:
// Example 2:
// Input: nums = [1,3]
// Output: [3,1]
// Explanation: [1,null,3] and [3,1] are both height-balanced BSTs.
// Constraints:
// 1 <= nums.length <= 104
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* sortedArrayToBST(vector<int>& nums) {
return sortedArrayToBSTHelper(nums, 0, nums.size()-1);
}
private:
TreeNode* sortedArrayToBSTHelper(const vector<int>& nums, int start, int end) {
if(start>end){
return nullptr;
}
int mid=start+(end-start)/2;
TreeNode* root=new TreeNode(nums[mid]);
root->left=sortedArrayToBSTHelper(nums,start,mid-1);
root->right=sortedArrayToBSTHelper(nums,mid+1,end);
return root;
}
};