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Copy path24.两两交换链表中的节点.go
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24.两两交换链表中的节点.go
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/*
* @lc app=leetcode.cn id=24 lang=golang
*
* [24] 两两交换链表中的节点
*
* https://leetcode-cn.com/problems/swap-nodes-in-pairs/description/
*
* algorithms
* Medium (59.65%)
* Likes: 206
* Dislikes: 0
* Total Accepted: 21.9K
* Total Submissions: 36.7K
* Testcase Example: '[1,2,3,4]'
*
* 给定一个链表,两两交换其中相邻的节点,并返回交换后的链表。
*
* 你不能只是单纯的改变节点内部的值,而是需要实际的进行节点交换。
*
*
*
* 示例:
*
* 给定 1->2->3->4, 你应该返回 2->1->4->3.
*
*
*/
/**
* Definition for singly-linked list.
* type ListNode struct {
* Val int
* Next *ListNode
* }
*/
func swapPairs(head *ListNode) *ListNode {
fast := head
slow := new(ListNode)
slow.Next = fast
if fast == nil || fast.Next == nil {
return head
}
result := fast.Next
for fast != nil && fast.Next != nil {
slow.Next = fast.Next
fast.Next = fast.Next.Next
slow.Next.Next = fast
slow = fast
fast = fast.Next
}
return result
}