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90.子集-ii.go
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import "sort"
/*
* @lc app=leetcode.cn id=90 lang=golang
*
* [90] 子集 II
*
* https://leetcode-cn.com/problems/subsets-ii/description/
*
* algorithms
* Medium (54.38%)
* Likes: 85
* Dislikes: 0
* Total Accepted: 7K
* Total Submissions: 12.8K
* Testcase Example: '[1,2,2]'
*
* 给定一个可能包含重复元素的整数数组 nums,返回该数组所有可能的子集(幂集)。
*
* 说明:解集不能包含重复的子集。
*
* 示例:
*
* 输入: [1,2,2]
* 输出:
* [
* [2],
* [1],
* [1,2,2],
* [2,2],
* [1,2],
* []
* ]
*
*/
func subsetsWithDup(nums []int) [][]int {
sort.Ints(nums)
result := make([][]int, 0)
n := len(nums)
if n <= 0 {
return result
}
stack := NewStack()
stack.Push(-1)
for stack.Size() > 0 {
top := stack.Pop() + 1
if top >= n {
continue
}
if top != 0 {
if nums[top] == nums[top-1] {
stack.Push(top)
continue
}
}
for i := top; i < n; i++ {
stack.Push(i)
result = append(result, buildStack(stack, nums))
}
}
result = append(result, buildStack(stack, nums))
return result
}
func buildStack(stack *Stack, nums []int) []int {
result := make([]int, 0)
for _, index := range stack.Values() {
result = append(result, nums[index])
}
return result
}
type Stack struct {
elements []int
}
func NewStack() *Stack {
return &Stack{
elements: make([]int, 0),
}
}
func (s *Stack) Push(val int) {
s.elements = append(s.elements, val)
}
func (s *Stack) Pop() int {
val := s.Top()
s.elements = s.elements[:len(s.elements)-1]
return val
}
func (s *Stack) Size() int {
return len(s.elements)
}
func (s *Stack) Top() int {
return s.elements[len(s.elements)-1]
}
func (s *Stack) Values() []int {
return s.elements
}