a = (4, 5, 6, 9, 2)
a[0] # O(1)
len(a) # O(1)
a[2:4] # O(4 - 2) => O(j - i)
b = [1, 3]
tuple(b) # O(len(b)) => O(N)
a == b # O(N)
a != b # O(N)
v = 9
v in a # O(N)
min(a) # O(N)
max(a) # O(N)
for v in a # O(N)
3 * a # O(3N) => O(kN)