Java-If-Else.java

/*
Problem Statement 4: Java If-Else
In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Task
Given an integer,n , perform the following conditional actions:

If  is n odd, print Weird
If  is n even and in the inclusive range of 2 to 5, print Not Weird
If  is n even and in the inclusive range of  to 6 20, print Weird
If  is n even and greater than 20, print Not Weird
Complete the stub code provided in your editor to print whether or not n is weird.

Input Format

A single line containing a positive integer, n.

Constraints
1 <= n <= 100
Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3
Sample Output 0

Weird
Sample Input 1

24
Sample Output 1

Not Weird

Explanation

Sample Case 0:n=3
n is odd and odd numbers are weird, so we print Weird.

Sample Case 1:n=24
n>20 and n is even, so it isn't weird. Thus, we print Not Weird.
 */
import java.io.*;
import java.util.*;

public class Solution3 {

    public static void main(String[] args) {
        Scanner sc= new Scanner(System.in);
        int n = sc.nextInt();
        if(n%2 ==0){
            if(n>=2 && n<=5){
                System.out.println("Not Weird");
            }
            else if(n>=6 && n<=20){
                System.out.println("Weird");
            }
            else{
                System.out.println("Not Weird");
            }
        }
        else{
            System.out.println("Weird");
        }

    }
}