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Copy path1031_Maximum-Sum-of-Two-Non-Overlapping-Subarrays.py
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1031_Maximum-Sum-of-Two-Non-Overlapping-Subarrays.py
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#Reference on https://leetcode.com/problems/maximum-sum-of-two-non-overlapping-subarrays/discuss/1012572/Python3-dp-(prefix-sum)
class Solution:
def maxSumTwoNoOverlap(self, A, L, M):
prefix = [0]
for x in A: prefix.append(prefix[-1] + x)
ans = lmx = mmx = float('-inf')
for i in range(M+L, len(A)+1):
lmx = max(lmx, prefix[i-M] - prefix[i-M-L])
mmx = max(mmx, prefix[i-L] - prefix[i-M-L])
ans = max(ans, lmx + prefix[i] - prefix[i-M], mmx + prefix[i] - prefix[i-L])
return ans
def main():
sol = Solution()
A = [0,6,5,2,2,5,1,9,4]
L = 1
M = 2
#Output: 20
print(sol.maxSumTwoNoOverlap(A, L, M))
A = [3,8,1,3,2,1,8,9,0]
L = 3
M = 2
#Output: 29
print(sol.maxSumTwoNoOverlap(A, L, M))
A = [2,1,5,6,0,9,5,0,3,8]
L = 4
M = 3
#Output: 31
print(sol.maxSumTwoNoOverlap(A, L, M))
A = [4,0,1]
L = 2
M = 1
#Output: 5
print(sol.maxSumTwoNoOverlap(A, L, M))
A = [4,5,14,16,16,20,7,13,8,15]
L = 3
M = 5
#Output: 109
print(sol.maxSumTwoNoOverlap(A, L, M))
A = [0,6,5,2,2,5,1,9,4]
L = 1
M = 2
#Output: 20
print(sol.maxSumTwoNoOverlap(A, L, M))
if __name__ == '__main__':
main()